KOREATECH 1071: 암호 해석 - 오고고

Link : judge.koreatech.ac.kr/problem.php?id=1071

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Python

from sys import stdin
 
data_length = int(stdin.readline().strip())
 
data_arr = stdin.readline().strip()
 
while True:
    str_idx = data_arr.find("ogo")
    if str_idx == -1:
        break
 
    next_pos = 0
    for i in range(str_idx, len(data_arr) - 1, 2):
        if i + 3 < len(data_arr):
            if data_arr[i + 3] == 'g' and data_arr[i + 4] == 'o':  # 다음이 go로 이루어져있다면
                next_pos += 2
            else:  # 계속할 go가 없다면
                data_arr = data_arr[:str_idx] + '***' + data_arr[str_idx + next_pos + 3:]
                break
        else:  # 쌓아둔 next_pos 만큼 모두 변환
            data_arr = data_arr[:str_idx] + '***' + data_arr[str_idx + next_pos + 3:]
            break
 
print(''.join(data_arr))
 

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